Constructing and testing an electronic circuit with first order low pass filter

Discussion in 'The Projects Forum' started by gaffer, Aug 28, 2009.

1. gaffer Thread Starter New Member

Aug 28, 2009
1
0
Hi, was just wondering if anyone could help.
This is a university project i have been given. Im very unexperienced in this area of electronics so i am really struggling, especially with the measurements and calculations side of the experiment. Here is the basics of the assessment.

You are required to produce a report detailing how you would construct and test an electronic circuit.

You need to detail a circuit comprising of a resistor of 1 KΩ and a capacitor to produce:
(i) a first-order low pass filter with a cut off frequency of 2.5KHz
(ii) a first order high pass filter with a cut off frequency of 4KHz
You are required to produced a circuit diagram for each case, and calculate the value of the capacitor required to meet the frequency response requirements stated.

This may seem like an easy task, but as i said i have absolutely no experience with this and find it difficult to state the measurements and calculations needed due to the fact i am not actually taking part in the experiment, only writing a report about it.

If anyone could help or point me in the right direction i will be very grateful,

2. Audioguru New Member

Dec 20, 2007
9,411
896
A first-order filter is extremely simple because it has only two parts.
The frequency calculation is also extremely simple.

Why are you writing a report about an electronics circuit that you know nothing about?

May 11, 2009
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4. rogs Active Member

Aug 28, 2009
279
37
As you are only writing a report on how to do this, rather than showing your understanding of the mathematical details of actual filter design, why not use a 'real world' solution, and let others worry about the academics?

This: http://focus.ti.com/docs/toolsw/folders/print/filterpro.html is a free application that will simply let you enter the parameters you need, and give you the results for the components you require.
Can't see the point of getting involved in detailed filter maths, if you don't have to, when someone's already done it for you, and made it available for free!

Typical results for your specific filters:

Last edited: Aug 29, 2009