Confusion calculating AC power, induction motor

Discussion in 'Homework Help' started by poopscoop, Feb 11, 2015.

  1. poopscoop

    Thread Starter Member

    Dec 12, 2012
    139
    16
    I have an induction motor with a voltage of 120 at 0degrees, and current of 1 amp at -30 degrees relative.

    Finding the complex power:
    P = VI * cos(angle(voltage) - angle(current)
    P = 120 * 1 * cos(0 - (-30))
    P = 120*cos(30)

    Correct?

    Therefore Q will be:
    Q = VI*sin(0 -(-30))

    Which will give me a positive P and a positive Q. If this were a capacitive load, I would have a negative Q, correct?
     
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