Concept of inductor

Discussion in 'General Electronics Chat' started by elecidiot, Nov 27, 2010.

  1. elecidiot

    Thread Starter New Member

    Jun 29, 2010
    23
    0
    I came across this problem which is attached here as a jpg file. In the problem the switch is opened at t=0. The initial conditions before opening of switch ie at t=0- is iL1=E/R and iL2=E/(2R). This I can understand. But for finding iL1(0+) and iL2(0+) the equation
    (L1+L2)i(0+)=L1(iL1(0-))+L2(iL2(0-)) is used. How this equation is got? Does this means that the currents in both L1 and L2 are changed instantaneously? Please help. See the attachment for the circuit.
     
  2. thatoneguy

    AAC Fanatic!

    Feb 19, 2009
    6,357
    718
    Is this a homework assignment?

    Inductor currents do not start instantly, they resist a change in the flow of current, whether it is none, or 1 amp.
     
  3. elecidiot

    Thread Starter New Member

    Jun 29, 2010
    23
    0
    this is not a homework assignment. this was worked out in class. i just wanted to know how this equation (L1+L2)i(0+)=L1(iL1(0-))+L2(iL2(0-)) came. Please explain that.
     
Loading...