Hi Guys, I have a question thats bugging me, if you can help. I need to calculate Is when I1 = 4 + j10 Z1= 9+J10 Z2=2 + j6. Is= I1x Z1/Z1 + Z2. Is this just multiplying by the complex conjugate? Would I just do (9 +j10) (9 +j10 + 2 + j6) = (9 +j10) x (11 - j16) (11 +j16) (11 - j16 Then multiply the answer by I1 which would be 4? Thanks Guys.
Hello, Let me check first whether I get what you means. Is the equation below same with yours? If yes then your steps are correct, but the final answer is not equal to 4.
This equation has units problems. Z1/Z1 is simply 1 (no units), so (Z1/Z1 + Z2) is (1 + Z2) and you can't add something that has no units to something that has units of impedance (i.e., ohms). Normally, if you have a Z1 and then talk about I1, it means that I1 is the current through Z1. But if I use that convention, then I have no idea what you are trying to do. It would really, really help if you provided a circuit, or at least a description of a circuit, so that we didn't have to try to read your mind.