Complex Boolean Algebra

Discussion in 'Homework Help' started by StrikeZero, Feb 9, 2010.

  1. StrikeZero

    Thread Starter New Member

    Feb 9, 2010
    2
    0
    The Question says:
    Simplify the expression
    (ABC)'(A+DE)(A+B'C)(B+E)
    and convert it to a form that can be represented using a programmable logic array.


    I'm having trouble simplifying the expression. I know that (ABC)' becomes (A'+B'+C'), but then I'm lost. Do I really distribute all of this out? Is there some kind of other way? I tried distributing for a bit and the variables are just so long and mind boggling.
     
  2. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    Then multiply all the terms and some will equal zero or one.
     
  3. StrikeZero

    Thread Starter New Member

    Feb 9, 2010
    2
    0
    Okay, thanks.
     
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