communication

Discussion in 'Homework Help' started by asan80, Jul 20, 2011.

  1. asan80

    Thread Starter New Member

    Jul 17, 2011
    1
    0
    a normal AM transmitter produces a total output of 24kw when modulated to a depth of 100% determine the power output when the carrier is modulated to a depth of 60%, one sideband is suppressed and the carrier components is attenuated by 26dB?
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    For AM

    \frac{P_c}{P_t}=\frac{1}{(1+\frac{m^2}{2})}

    Pc= Carrier Power
    Pt=Total power (Carrier power + two sidebands of equal power)
    m=modulation index (as a fraction).

    This might be a useful starting point.

    With m=1 you are given Pt=24kW.

    Calculate the carrier power and proceed with the new conditions applied to find the new total power at 60% modulation (m=0.6). You will then be able to deduce the sideband powers. And so on.
     
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