# communication

Discussion in 'Homework Help' started by asan80, Jul 20, 2011.

1. ### asan80 Thread Starter New Member

Jul 17, 2011
1
0
a normal AM transmitter produces a total output of 24kw when modulated to a depth of 100% determine the power output when the carrier is modulated to a depth of 60%, one sideband is suppressed and the carrier components is attenuated by 26dB?

2. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
782
For AM

$\frac{P_c}{P_t}=\frac{1}{(1+\frac{m^2}{2})}$

Pc= Carrier Power
Pt=Total power (Carrier power + two sidebands of equal power)
m=modulation index (as a fraction).

This might be a useful starting point.

With m=1 you are given Pt=24kW.

Calculate the carrier power and proceed with the new conditions applied to find the new total power at 60% modulation (m=0.6). You will then be able to deduce the sideband powers. And so on.