Hi,
I have the following question
Calculate the common voltage [Vc] and diferential voltage [Vd] in the input of the opamp considering that the error is 10% when Vin=1.5 V
I know that \( Vd=Vp-Vn
Vc=(Vp+Vn)/2
Vo=Ad(Vp-Vn)+Ac(Vp+Vn)/(2)) \)
The information that the error is 10% when Vin=1.5 V what does that tell me about the opamp?
What is considered to be the error of an ampop?Is the common voltage that is amplified and it shouldn't?
Does that tell me that \( 0.15V (10% of 1,5V)=(Vp+Vn)/2
0.15V=(Vp+1,5)/2\)
Thank you
I have the following question
Calculate the common voltage [Vc] and diferential voltage [Vd] in the input of the opamp considering that the error is 10% when Vin=1.5 V
I know that \( Vd=Vp-Vn
Vc=(Vp+Vn)/2
Vo=Ad(Vp-Vn)+Ac(Vp+Vn)/(2)) \)
The information that the error is 10% when Vin=1.5 V what does that tell me about the opamp?
What is considered to be the error of an ampop?Is the common voltage that is amplified and it shouldn't?
Does that tell me that \( 0.15V (10% of 1,5V)=(Vp+Vn)/2
0.15V=(Vp+1,5)/2\)
Thank you