Common Emitter Amplifier Stage Design Question

Discussion in 'Homework Help' started by derail, Aug 13, 2009.

  1. derail

    Thread Starter New Member

    Aug 13, 2009
    2
    0
    Hi, I'm currently trying to solve a problem involving the design of a common emitter amplifier stage in an autobias configuration. The information I'm given is that

    Vcc=12
    Vbe=0.7
    gm=0.12
    hfe=120
    RS=500
    RL=1000
    Gv=29.5dB
    There should be max power transfer from source to load and max output voltage swing under AC.

    So far I have calculated values for Rc and R1//R2 due to the requirement for max power transfer so that
    RC=1000
    R1//R2=1000

    However I'm now stuck trying to find a value for RE and individual values for R1 and R2. I know it has something to do with calculating the quiescent collector current using the AC load line, and that Vce will be 0 thus eliminating it from calculation.

    Essentially I need to work out how to find a value for RE. Ive attached a circuit diagram and any help would be greatly appreciated. Also i welcome any questions or discussions on my own thoughts how to solve this no matter how wrong i may be, ive been going round in circles for hours.
     
  2. Jony130

    AAC Fanatic!

    Feb 17, 2009
    3,957
    1,097
    The rule of a thumb for Re
    Re=(0.1...0.3)Ucc/Ic
    Ic=gm*26mV=3.12mA

    And R1 and R2 select to achieve the quiescent collector current.
    For example if we pick
    Re=1V/Ic=330Ω
    You must select the voltage divider R1 and R2 that they give the 1.7V on the base. And current that is flow through R1 and R2 should be large then Ib.
    And remember that
    Gv= Rin/(Rin+Rs) * ( gm*Rc||RL)=29.5dB=29.8V/V

    Rin=R1||R2||( Hfe/gm)
     
  3. The Electrician

    AAC Fanatic!

    Oct 9, 2007
    2,281
    326
    Jony130, you're not supposed to work out the problem for the OP. You're supposed to give him hints to help him do the work himself.

    I think I would have started by telling him that Ic=gm*26mV, and let him proceed from there. You could tell him that if he still has difficulty, then come back to the forum and show his work up to that point, and ask for more help.
     
  4. derail

    Thread Starter New Member

    Aug 13, 2009
    2
    0
    Thanks for the quick replies though im not sure where you got the 26mV from, no where in any of the previous examples ive done, nor in teaching notes have i seen Ic=gm*26mV.
     
  5. ELECTRONERD

    Senior Member

    May 26, 2009
    1,146
    16
    Yep, that's right. Although, once he does come up with the answers it's ok to share yours so he can check his work.
     
  6. Jony130

    AAC Fanatic!

    Feb 17, 2009
    3,957
    1,097
    THX ,I will keep that in mind.
     
  7. ELECTRONERD

    Senior Member

    May 26, 2009
    1,146
    16
    No sweat! ;)
     
  8. The Electrician

    AAC Fanatic!

    Oct 9, 2007
    2,281
    326
    Have you seen the formula re = .026/Ie?

    Have a look at http://en.wikipedia.org/wiki/Transconductance

    under the heading "Bipolar transistors". You'll find the formula gm = Ic/VT, where VT= .026 V.
     
Loading...