Hi,
I am stuck on part (a) of this question:
I am not sure where I am going wrong exactly:
I calculate the voltage at the base of the transistor to be at 20*(43/(43+330) since the two resistors act as potential dividers.
This voltage is 2.31V. (Vb=2.31V)
Now if we assume the transistor to be on, the Vbe=0.7. So Ve=2.31-0.7=1.61V
If there is 1.61V across the 1.5kΩ resistor, the current must be I=V/R=1.61/1.5k=1.07mA. This is current Ie.
Ic=αIe. Where α=β/(β+1) and Ie=1.07mA ==> Ic=(200/201)*1.07m=1.06mA
I don't see any mistaking in my method but the answer is given as Ic=0.946mA.
Can someone explain?
I am stuck on part (a) of this question:
I am not sure where I am going wrong exactly:
I calculate the voltage at the base of the transistor to be at 20*(43/(43+330) since the two resistors act as potential dividers.
This voltage is 2.31V. (Vb=2.31V)
Now if we assume the transistor to be on, the Vbe=0.7. So Ve=2.31-0.7=1.61V
If there is 1.61V across the 1.5kΩ resistor, the current must be I=V/R=1.61/1.5k=1.07mA. This is current Ie.
Ic=αIe. Where α=β/(β+1) and Ie=1.07mA ==> Ic=(200/201)*1.07m=1.06mA
I don't see any mistaking in my method but the answer is given as Ic=0.946mA.
Can someone explain?