# Circuit output for complex exponential input

Discussion in 'Homework Help' started by tquiva, Jan 26, 2011.

1. ### tquiva Thread Starter Member

Oct 19, 2010
176
1

Here's my current approach:

I think I did it correctly? But not too sure about finding the output for a very small complex frequency and very large complex frequency.

Does this mean that for when t = ∞, the capacitor becomes a short? Then I would just go with the same approach as in my above solution?

For t = -∞, I'm not exactly sure what happens. Do the capacitors become open circuits??

If someone could please point me in the right direction or help me with suggestions, I would really appreciate it. I am just really confused right now...

2. ### mik3 Senior Member

Feb 4, 2008
4,846
63
You need to find I through L and not through Z.

Calculate R//C and then use the current divider rule to find the current through L.

3. ### narasimhan Member

Dec 3, 2009
72
6
I guess very small freq means capacitor is open and very large freq means the inductor is open. But that's just ideal case.