Circuit output for complex exponential input

Discussion in 'Homework Help' started by tquiva, Jan 26, 2011.

  1. tquiva

    Thread Starter Member

    Oct 19, 2010
    176
    1
    Could someone please help me solve this given problem:

    Problem2.jpg

    Here's my current approach:

    Solution1.jpg

    I think I did it correctly? But not too sure about finding the output for a very small complex frequency and very large complex frequency.

    Does this mean that for when t = ∞, the capacitor becomes a short? Then I would just go with the same approach as in my above solution?

    For t = -∞, I'm not exactly sure what happens. Do the capacitors become open circuits??

    If someone could please point me in the right direction or help me with suggestions, I would really appreciate it. I am just really confused right now...
     
  2. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    You need to find I through L and not through Z.

    Calculate R//C and then use the current divider rule to find the current through L.
     
  3. narasimhan

    Member

    Dec 3, 2009
    72
    6
    I guess very small freq means capacitor is open and very large freq means the inductor is open. But that's just ideal case.
     
Loading...