Hello, I have the attached circuit which I am trying to solve. I 'think' I have all the currents correct, however I am struggling to make the voltage drops over the resistors in the right hand loop(2) equate to 0 as per Kirchoff's law of voltages. The two resistors on the left hand loop(1) drop the power source to 0, so that loop is fine. It is the big loop on the right that I am having trouble with. If someone could please take a look and tell me where I am going wrong that would be much appreciated. Thanks kindly.
R4 is not in the loop for the voltage calculation. And, the voltage drop over the final resistors should also give you a (-) sign. 12 - 4 - 2.67 - 5.33 = 0
The reason that your voltage summation fails for the right-hand side of your circuit is that you are using voltage multiple time. Notice that if you had stopped at 12-4-8 = 0 you would have solved the first loop. The 2.66v and 5.333v figures associate with the rightmost loop only. hgmjr
For lopp 1: 12 = I1 (9Ω + 1Ω) so I1 = 12/10Ω = 1.2Amp but in the opposite direction that you draw I1 For the loop 2 R2 = 2Ω . . . . Req = 12Ω //6Ω gives 4Ω so the total resistance in the right side is Rt = 6Ω = 2Ω+4Ω and current I2 = 12V/6Ω= 2Amp that flow throug R2