What is the change in entropy when 1gram of ice at 0° C is converted into water at the same temperature? My attempt at the solution. dS = dQ/T, where S is entropy, Q is heat energy and T is absolute temperature. Again Q = mass X specific heat capacity X Change in temperature(ΔT) T in the denominator is absolute temperature so 0+273 = 273K. mass = 1 gm. I don't know what to substitute for sp.heat capacity? Whether sp.heat of water or sp.heat of ice? Again for ΔT, what values to substitute? Revered members can help.
Thanks russ_hensel. So dS = 1X80(latent heat of fusion of ice)/273K which gives 0.293cal/K. Am i right?