Change in entropy

Discussion in 'Physics' started by logearav, Dec 14, 2011.

  1. logearav

    Thread Starter Member

    Aug 19, 2011
    What is the change in entropy when 1gram of ice at 0° C is converted into water at the same temperature?
    My attempt at the solution.
    dS = dQ/T, where S is entropy, Q is heat energy and T is absolute temperature.
    Again Q = mass X specific heat capacity X Change in temperature(ΔT)
    T in the denominator is absolute temperature so 0+273 = 273K.
    mass = 1 gm. I don't know what to substitute for sp.heat capacity? Whether sp.heat of water or sp.heat of ice? Again for ΔT, what values to substitute? Revered members can help.
  2. russ_hensel

    Well-Known Member

    Jan 11, 2009
    Why does specific heat matter? Think about its definition. Then think about heat of fusion.
    logearav likes this.
  3. logearav

    Thread Starter Member

    Aug 19, 2011
    Thanks russ_hensel. So dS = 1X80(latent heat of fusion of ice)/273K which gives 0.293cal/K. Am i right?