Problem: A 3.00uF and a 4.0uF capacitor are connected in series and this combination is connected in parallel with a 2.0uF capacitor. If 26V is applied across the whole network, calculate the voltage across each capacitor. (See attached figure)
My Attempt/Questions:
So my thought was to find the total charge and the total capacitance and use V= Q/C to find the voltage across each
so the total capacitance will be 1/(.33 +.25) +2 = 3.71uF
then the total charge by Q=CV = 3.71 x 26 = 96.5 uC
so the voltage at 2.0uF capacitor will be V=Q/C = 96.5/2 = 48.2V
What I don't get now is how I relate what I know to the remainder of the parallel series at the top of the box. I know that the voltage wont be split evenly between them, but that they will share the same amount as the one in parallel. That is to say capacitor 3.0 and 4.0 should have a cumulative voltage of 48.2V but that it wont be split evenly between them.
Is this correct, and if so how do I go about calculating that? Thanks
My Attempt/Questions:
So my thought was to find the total charge and the total capacitance and use V= Q/C to find the voltage across each
so the total capacitance will be 1/(.33 +.25) +2 = 3.71uF
then the total charge by Q=CV = 3.71 x 26 = 96.5 uC
so the voltage at 2.0uF capacitor will be V=Q/C = 96.5/2 = 48.2V
What I don't get now is how I relate what I know to the remainder of the parallel series at the top of the box. I know that the voltage wont be split evenly between them, but that they will share the same amount as the one in parallel. That is to say capacitor 3.0 and 4.0 should have a cumulative voltage of 48.2V but that it wont be split evenly between them.
Is this correct, and if so how do I go about calculating that? Thanks
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