a) The capacitor is uncharged when the switch is thrown into position 1. The switch remains in position 1 for 10msec and then is thrown into position 2, where it remains indefinitely. Draw the complete waveform for the capacitor voltage. b) If the switch is thrown back to position 1 after 5ms in position 2, and then is left in position 1, how will the waveform appear? I'm not sure how to proceed with this problem. I was thinking this way: while switch is in position 1 for 10msec i calculated voltage of capacitor at 10msec. First i found time constant at position 1, RC=(R1+R2)*1μF=55msec Then i calculated Vc at 10msec: Vc=(Vfinal-Vinitial)(1-e^-t/RC) Vc=20V(1-e^-10/55)=3.32V So Capacitor voltage is 3.32V, then switch thrown into position 2. I think that when switch thrown in pos 2, capasitor starts dischargin so I'd use discharging formula. First I found pos 2 time constant RC=(R2||R3)*1uF=7.67msec Did i proceed in right way till this point? If so, how do i find in what time capacitor discharged to 0V? And how can i draw waveform for capacitor voltage? I didn't start on b) part yet.