Capacitor charging

Thread Starter

Sparky49

Joined Jul 16, 2011
833
Hi all.

I know we can use the V(t)=Vi(1-e^(-t/RC)) equation to get the discharge time for a capacitor, but I am stuck when it comes to another formula.

I need to figure out the time to get to 10Volts, when 1mA current charges a 1uF capacitor.

I know that I=C(dV/dt), and have rearranged to get V(t)=(I/C)t, however I am not sure where to go from here.

Many thanks.

Sparky
 

MrChips

Joined Oct 2, 2009
30,810
Actually, no. You have the wrong equation and the right equation.
The equation for discharge is V(t)=Vi(e^(-t/RC)).
What you have shown is the equation for charging.
 

bretm

Joined Feb 6, 2012
152
You have V(t)=(I/C)t. You know V(t)=10V, you know I=1mA, you know C=1uF, you just need to know t.

10V = (1mA / 1uF) t = (1000 V/s) t

So t=10ms
 

MrChips

Joined Oct 2, 2009
30,810
I am sorry I misread the question. bretm is correct. Since the charging current is constant, V(t) increases linearly with t.
 
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