# Can someone help me solving the circuit attached?

Discussion in 'Homework Help' started by i_nour, Nov 9, 2015.

Nov 9, 2015
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2. ### Jony130 AAC Fanatic!

Feb 17, 2009
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Can we see your attempt first ??

Tip - don't forget to connect the GND together

3. ### i_nour Thread Starter New Member

Nov 9, 2015
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I tried to solve it, but then I realized that Vout shouldn't be 100. I get confused.
also I didn't know how to connect GND together

4. ### Jony130 AAC Fanatic!

Feb 17, 2009
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Try again but this time with this redrawn circuit by me:

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5. ### i_nour Thread Starter New Member

Nov 9, 2015
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It worked ! thank you

6. ### Jony130 AAC Fanatic!

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It wasn't that hard after all ?

7. ### i_nour Thread Starter New Member

Nov 9, 2015
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yeah
well, can I redraw this circuit in that way?

8. ### Jony130 AAC Fanatic!

Feb 17, 2009
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Yes you can, but this circuit is tricky.

9. ### i_nour Thread Starter New Member

Nov 9, 2015
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I found that the sum of the branched currents is bigger than the primary current..why? how to solve it?

10. ### Jony130 AAC Fanatic!

Feb 17, 2009
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Because in this case only one of the two diodes can conduct, and your job is to find out which one it is (based on circuit analysis).

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11. ### i_nour Thread Starter New Member

Nov 9, 2015
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I think the solitary one is off, and the other is on
you helped me, thank you

12. ### Jony130 AAC Fanatic!

Feb 17, 2009
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Do you have any proof for that ??

13. ### i_nour Thread Starter New Member

Nov 9, 2015
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The positive terminal of the first battery is connected to the anode while the positive terminal of the second battery is connected to the cathode and because the batteries are equivalent, they canceled out each other. Is it right?

Feb 17, 2009
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