Hi everyone.
I want to design a chopper circuit to modulate the very low frequency differential signal to 1kHz signal in order to limit 1/f noise. I choose H-bridge to connect a transformer to do this job. My question is: Can I use two inverters to implement the H-Bridge?
Two inverters are connected in parallel. Sources of two PMOS are connected to +ve signal rail and sources of NMOS are connected to -ve signal rail. The outputs of two inverters are connected to transformer which is used to isolate from op-amp.
I find that if two inverters are controlled by two anti-phase clock, one of NMOS and PMOS will be turned on at either side (but not at same side). For a eg, in the first half cycle, the right side inverter is input '1' and left side is input '0'. Then NMOS at left side and PMOS at right side will be turned on, the rest MOS will turned off. So, the current will flow from right to left. Similarly, in the second half cycly, it will flow from left to right.
Do I understand this operation correctly? I notice that there is no Vdd and Gnd in this part of circuit, instead there are differential signals. So does it mean this two points are floating?
Sorry for my poor English and hope you guys could understand what I said.
I want to design a chopper circuit to modulate the very low frequency differential signal to 1kHz signal in order to limit 1/f noise. I choose H-bridge to connect a transformer to do this job. My question is: Can I use two inverters to implement the H-Bridge?
Two inverters are connected in parallel. Sources of two PMOS are connected to +ve signal rail and sources of NMOS are connected to -ve signal rail. The outputs of two inverters are connected to transformer which is used to isolate from op-amp.
I find that if two inverters are controlled by two anti-phase clock, one of NMOS and PMOS will be turned on at either side (but not at same side). For a eg, in the first half cycle, the right side inverter is input '1' and left side is input '0'. Then NMOS at left side and PMOS at right side will be turned on, the rest MOS will turned off. So, the current will flow from right to left. Similarly, in the second half cycly, it will flow from left to right.
Do I understand this operation correctly? I notice that there is no Vdd and Gnd in this part of circuit, instead there are differential signals. So does it mean this two points are floating?
Sorry for my poor English and hope you guys could understand what I said.