anyone who can haelp me about this?
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Is there any other information given? For example, was the Vbe for the transistors used provided as part of the problem statement?anyone who can haelp me about this?
Can you explain how/why it's wrong? Generally, answers can be right or wrong, but questions are usually good or bad. Although, occasionally a question is so bad that it is reasonable to call it "wrong".the question is wrong.
the BJTs are turn ON and have a Vbe of 650mvIs there any other information given? For example, was the Vbe for the transistors used provided as part of the problem statement?
hgmjr
Why don't like the one I suggested? Ie=Is*(exp(Vbe/nVt)-1)... how about the current for Output BJT's
That's LN for natural logarithm. Just take the inverse operation of the exponential function.what In stadss for?
what shoulb be the value for this?
thanks...
Ohms law is just V=IR, so R=.47 Ohms and I=Ie as found in solving the equation 0.15V=Ie*(0.47ohms)+nVt*ln(Ie/Is+1) using a numerical technique such as Newton's method, or search algorithm.thanks steve
what if I used the Ohm law for calculating the Voltage across 0.47 ohm resistor, what will be be the formula for this?
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