Hi Everyone ,
I am doing what I though was a simple calulation and getting a funny result. Maybe someone could help me out with this:
I need to calculate the cross section of solid Aluminum needed to handle 150Amps @ 20V, used by my group for a 75 cm long piece of solid square aluminium. Assume Temperature K = 298
What Ive done so far:
1.V=IR 20 = 150*R R= 20/150 R=0.1333
2.R=pl/A
RESISTIVITY:
p= 2.709X10^-8 OHM*m
p(cm) = 2.709X10^-6OHM*cm
LENGTH:
l=75cm
I substitute R from Ohms Law into equation and solve for A.
A=pl/R A= 1.5698X10^-3 cm*cm
This seems to small.
I compare this to the awg of Aluminum required to handle 150A = Size 0
TO CALCULATE CROSS SECTION OF 1/0 WIRE:
n = −(m−1) where m=1, n = 0, plugging into d = .005"*92^(36-n/39)
D=diameter=0.324"
AREA=(PI*D^2)/4 = 82.88X10^-3"^2 = cross section for 1/0 wire which handles 150Amps.
this is much bigger then my calc.
Why is my calculation so off?
Thank you in advance!
I am doing what I though was a simple calulation and getting a funny result. Maybe someone could help me out with this:
I need to calculate the cross section of solid Aluminum needed to handle 150Amps @ 20V, used by my group for a 75 cm long piece of solid square aluminium. Assume Temperature K = 298
What Ive done so far:
1.V=IR 20 = 150*R R= 20/150 R=0.1333
2.R=pl/A
RESISTIVITY:
p= 2.709X10^-8 OHM*m
p(cm) = 2.709X10^-6OHM*cm
LENGTH:
l=75cm
I substitute R from Ohms Law into equation and solve for A.
A=pl/R A= 1.5698X10^-3 cm*cm
This seems to small.
I compare this to the awg of Aluminum required to handle 150A = Size 0
TO CALCULATE CROSS SECTION OF 1/0 WIRE:
n = −(m−1) where m=1, n = 0, plugging into d = .005"*92^(36-n/39)
D=diameter=0.324"
AREA=(PI*D^2)/4 = 82.88X10^-3"^2 = cross section for 1/0 wire which handles 150Amps.
this is much bigger then my calc.
Why is my calculation so off?
Thank you in advance!