Calculating the Hysteresis Power Loss

Discussion in 'Homework Help' started by nyasha, Jan 17, 2012.

  1. nyasha

    Thread Starter Active Member

    Mar 23, 2009
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    I am a bit confused on how l incorporate the area of the hysteresis loop into all this. Do l just plus in the 6.25 square centimetres or l have to do something with the relations of H and B which they gave me.
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    The B-H plot on graph paper is giving 6.25cm^2 for the hysteresis loop area.

    Scaling of the graph paper area gives 1cm^2 <=> 50[At/m]*0.2[T]=10 Joules per m^3.

    So 6.25cm^2 <=> 62.5 J/m^3

    You have a core volume of 450 cm^3 <=> 450x10^-6 m^3

    At 60Hz you then find the power in MKS [SI] system units.
     
  3. nyasha

    Thread Starter Active Member

    Mar 23, 2009
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    1
    Another thing which l do not understand is how to calculate the power in watts/kg. In my calculations l have J/s and l am given the density. I do not know to calculate for the
     
    Last edited: Jan 17, 2012
  4. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    Your PH will come out directly as Watts - [1Watt=J/s]

    So you have a certain value in Watts for a given volume. That can be equated to the same watts for a given mass since mass=volume x density.

    You didn't state what the density is but if it's for transformer steel the typical density is ~7600kg/m^3.

    So a volume 450cm^3 has a mass of ~3.4kg.

    So if it is steel with that density your PH/3.4 gives the watts per kg ......
     
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