Calculating current in RLC Series Circuit

Discussion in 'Homework Help' started by agroom, May 9, 2011.

  1. agroom

    Thread Starter Active Member

    Oct 15, 2010
    60
    1
    I've got a homework problem I got wrong. After consulting the book for help, I came up with these answers in the table below. Could anyone help verify if they are correct? There's also a few values that I'm missing and don't really know how to get them marked with a question mark

    Sorry, no picture of the circuit, it's an RLC series circuit with the following values:

    Vs = 1v p-p
    fs = 5KHz

    R = 1,000 Ω
    C=0.039μF
    L=3mH

    Table:
    Parameter | Magnitude | Angle

    Xc | 816.18 Ω | -90°
    Xl | 94.25 Ω | 90°
    Xtotal | -721.93 Ω | ?
    Z | 1,233.36 Ω | -35.8°
    I | 0.81 mA | 35.8°
    Vc | 661.1 mV | -54.2°
    Vl | 76.3 mV | 125.8°
    Vr | 810 mV | 35.8°
    Vs | 1 V | 0°

    The current I calculated by:

    Vs/Z = 1V 0° / 1,233.36Ω -35.8° = .081mA 35.8°

    Then the voltage across each component

    Vc = (0.81 mA 35.8°) * (816.18Ω -90°)
    Vl = (0.81 mA 35.8°) * (94.25Ω 90°)
    Vr = (0.81 mA 35.8°) * (1,000Ω 0°)
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    Your answers are correct.:)
     
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