# Calculating current in RLC Series Circuit

Discussion in 'Homework Help' started by agroom, May 9, 2011.

1. ### agroom Thread Starter Active Member

Oct 15, 2010
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I've got a homework problem I got wrong. After consulting the book for help, I came up with these answers in the table below. Could anyone help verify if they are correct? There's also a few values that I'm missing and don't really know how to get them marked with a question mark

Sorry, no picture of the circuit, it's an RLC series circuit with the following values:

Vs = 1v p-p
fs = 5KHz

R = 1,000 Ω
C=0.039μF
L=3mH

Table:
Parameter | Magnitude | Angle

Xc | 816.18 Ω | -90°
Xl | 94.25 Ω | 90°
Xtotal | -721.93 Ω | ?
Z | 1,233.36 Ω | -35.8°
I | 0.81 mA | 35.8°
Vc | 661.1 mV | -54.2°
Vl | 76.3 mV | 125.8°
Vr | 810 mV | 35.8°
Vs | 1 V | 0°

The current I calculated by:

Vs/Z = 1V 0° / 1,233.36Ω -35.8° = .081mA 35.8°

Then the voltage across each component

Vc = (0.81 mA 35.8°) * (816.18Ω -90°)
Vl = (0.81 mA 35.8°) * (94.25Ω 90°)
Vr = (0.81 mA 35.8°) * (1,000Ω 0°)

Mar 6, 2009
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