butterworth filter

Papabravo

Joined Feb 24, 2006
21,159
For starters, I don't think your transfer function represents a Butterworth Filter. Why do you think it does?
Also -- what is with the negative resistance? No passive component is capable of having such a behavior.
 

Thread Starter

josh007

Joined Sep 20, 2015
43
For starters, I don't think your transfer function represents a Butterworth Filter. Why do you think it does?
Also -- what is with the negative resistance? No passive component is capable of having such a behavior.
Hi Sir. Please can you advise me on what needs to be done. I just feel like giving up on this subject. I need help please. Please guide me.

I thought to make it look like a third order butterworth filter. Where can I find info that will help me to answer this.

thanks
 

recklessrog

Joined May 23, 2013
985
Hi Sir. Please can you advise me on what needs to be done. I just feel like giving up on this subject. I need help please. Please guide me.

I thought to make it look like a third order butterworth filter. Where can I find info that will help me to answer this.

thanks

Go to www.nuhertz.com and download filter free 2012, very useful free software
 

Papabravo

Joined Feb 24, 2006
21,159
I think you might want to start with an expression for Zin(s). Hint: your schematic looks like the equivalent circuit for an active device. The diamond symbol with the arrow inside "looks like" a current source, but with a value of 2V1, it has the wrong units. If instead it is a voltage source, then you have an amplifier with a gain of 2. Knowing what that symbol represents would be most helpful.
 

Papabravo

Joined Feb 24, 2006
21,159
The picture of your work is very difficult to read, especially the subscripts, and the drawing is not labeled. So I don't know what the quantities refer to. Try not to take pictures of a page on an angle it hurts my eyes to try and read it.

Isn't
\(Z_{in}(s) = \frac{1}{1+2s}|_ {\scriptsize s=j\omega}\)
 
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