Boolean Logic

Discussion in 'Homework Help' started by ckaiser813, Sep 2, 2009.

  1. ckaiser813

    Thread Starter Member

    Jan 21, 2009
    17
    0
    Just checking if I'm right with these?

    Given F=A'B+(C'+E)(D+F'), use de Morgan's theorem to find F'

    I got F=A+B'(CE')+(D'F)????


    Simplify the following: {[(AB)'C]'D}'

    I got A'+(B'+C')D


    Pretty tough for me
     
  2. mkbutan

    Senior Member

    Sep 30, 2008
    270
    16


    pl explane your steps for the five input F
     
  3. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    ckaiser813,

    You need to read this thread and download this program.

    http://forum.allaboutcircuits.com/showthread.php?t=22347&highlight=BOOLEAN

    When you do plug in the Boolean expression, A'B+(C'+E)(D+F'), into the program, you will obtain the following minterms:

    0 2 4-7 10 14-32 34 36-39 42 46-48 50 52-55 58 62-63

    The negative of that expression should have the missing minterms of the above expression, which are:

    1 3 8-9 11-13 33 35 40-41 43-45 49 51 56-57 59-61

    Since your answer, A+B'(CE')+(D'F) does not these minterms, that is a sure indication that your result is wrong. Try again and use the program to check your new result.

    The program gives the minterms for ((AB)'C)'D as 1 5 9 13 15

    Your answer, A'+(B'+C')D, has minterms 0-7 9 11 13 , so again you have the wrong answer. Get the idea?

    Ratch
     
  4. ckaiser813

    Thread Starter Member

    Jan 21, 2009
    17
    0
    Thanks for your help, I'd never used that type of program but it help me understand what to look for. thanks again!
     
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