Boolean equations

Discussion in 'Math' started by kallen, Jun 2, 2004.

  1. kallen

    Thread Starter New Member

    Jun 2, 2004
    1
    0
    I am so confused, can someone pleaase help?

    Prove the identity of each of the following Boolean equations, using algebraic manipulation:

    a) AB + B C' D' + A' B C + C' D = B + C' D

    B) WY + W' Y Z' + WXZ + W' X Y' = WY + W' X Z' + X' Y Z' + X Y' Z

    c) A C' + A' B + B' C + D' = (A' + B' + C' + D')(A + B + C + D')

    The ' is the complement of the variable preceding it. Please help if anyone can.

    Thanks so much!!!!!
     
  2. susi

    Active Member

    Jun 4, 2004
    31
    0
    hi kallen,

    this is not too much difficult just to apply the Boolean Algebraic functions.I am also doing these things in these days as I have the course (Digital Logic design). I will give u the answer tommorrow.....for now m going to take a sleep zzzzzzzzzz
    shall write ya,
    susi
     
  3. beautifulmind

    New Member

    Mar 5, 2007
    4
    0
    Look at the colors before the equal sign and after it, and see how it is applied in the example.
    if you can visualise this i dont think you'll have a problem understadning and solving the rest. Match the colors and ull unederstand alot.

    X'Y+X =X+Y
    X+X' =1
    Y+1 =1

    A'B + A'BC + BC'D' +C'D
    =B(A+A'C) + C'(BD'+D)
    =B (A+C) + C'(B +D)
    =AB +BC +BC' +C'D
    =AB+B(C+C') + C'D
    =AB+B(1) +C'D
    =B(A+1) + C'D
    =b(1) +C'D
    =B +C'D

    if this is understood let me know so i can continue solving the rest they are quite simple an straight forward if u want me to explain in details also let me know. All the best sile
     
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