Boolean Equation Expression

Discussion in 'Homework Help' started by dukeofsmooth, Feb 15, 2009.

  1. dukeofsmooth

    Thread Starter New Member

    Feb 5, 2009
    2
    0
    Can someone please simplify the Boolean expression-
    AB'C + A'BC + A'B'C

    I worked the this expression in the following way...
    C(A'B + A'B' + AB')
    C[ A' (B + B') + AB']
    C[ A' (1) + AB']
    C(A' + AB')
    A'C + AB'C

    The text book answer is A'C + B'C

    Thank you,
    Jesse
     
    Last edited: Feb 15, 2009
  2. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    Hi there, Duke of Suave,

    Let's do your prob another way.

    C(A'B + A'B' + AB')
    C(A'B + A'B'+ A'B' + AB')
    C(A'(B + B') + (A' + A)B')
    C(A' + B')
    A'C + B'C and the answer book is correct.

    Or another way to solve it: your second to the last expression contains: A' + AB' .

    The dual is A'(A + B') which easily reduces to A'B' .

    Taking the dual again and multiplying by C gives C(A' + B') = A'C + B'C
     
Loading...