Boolean Algebra

Discussion in 'Homework Help' started by BruceBly, Nov 9, 2012.

  1. BruceBly

    Thread Starter New Member

    Jul 26, 2012
    25
    0
    Can anyone help me understand this?

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    I don't understand why the BC turn into a 0. Can someone explain that to me?
     
  2. debjit625

    Well-Known Member

    Apr 17, 2010
    790
    186
    Its already written their, the term BCAB' turns into 0 as for identity AA' = 0 in case of BCAB' the BB' = 0 ,So BCAB' = ACBB' = AC * 0 = 0
    You need to know DeMorgan’s theorem and Boolean arithmetic

    Good Luck
     
    BruceBly likes this.
  3. BruceBly

    Thread Starter New Member

    Jul 26, 2012
    25
    0
    That make more sense to me. Thanks...
     
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