boolean algebra

Discussion in 'Homework Help' started by Jdebeer123, Mar 12, 2011.

  1. Jdebeer123

    Thread Starter New Member

    Mar 12, 2011
    1
    0
    Hi there

    with regards to the question Cino had I am also having a bit of trouble.

    My effort so far is as follows then I get stuck.Please help

    F1 = x + x'(yw)' + w'y
    = 1(yw)' + w'y
    = 1(y' + w') + w'y
    = y' + w' + w'y
    =

    I cant seem to find any rules that apply to the last one

    Also F2 = (y' + x')'
    = y + x or would it be double Not's (y'' + x'')


    Please help

    Thanx

    [​IMG] [​IMG]
     
  2. justtrying

    Active Member

    Mar 9, 2011
    329
    351
    from your efforts, you can keep factoring = y' + w' + w'y = y'+w'(1+y) - does (1+y) equal anything? But I think you might want to review how you got x + x'(yw)' to reduce to 1(yw)' - it is true that x+x'=1, but that is not what I see in the question, unless you missed the brackets when posting it :)
     
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