Boolean Algebra

Discussion in 'Homework Help' started by scouser42, Feb 7, 2010.

  1. scouser42

    Thread Starter New Member

    Feb 7, 2010
    3
    0
    Hi everyone

    I'm presented with this problem and I'm thrown by the brackets, could any one offer any help please on how to work it out. The problem is:
    Z= (A.B.C) + (A.B.C.D)

    Thanks :confused:
     
  2. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    Z=ABC(1+D), ABC common factor

    Z=ABC, 1+D=1
     
  3. scouser42

    Thread Starter New Member

    Feb 7, 2010
    3
    0
    Thanks Mik thats a great help :D
     
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