Boolean algebra (POS) for circuit with NOR gates

Discussion in 'Homework Help' started by pixel1, Apr 17, 2013.

  1. pixel1

    Thread Starter New Member

    Apr 13, 2013
    Hi all,

    I'm trying to determine the correct way to decipher the Boolean expression for the circuit in the attached image. I have gone as far as working it out to be ((((A+B)A'+C)+B') as a product of sums expression. From here, what would be involved with simplifying this expression and circuit, still using only NOR gates? What working/steps need to be taken? I'm getting good at SOP but POS is turning out to be quite challenging :-(

    Thanks in advance for any help :)
  2. WBahn


    Mar 31, 2012
    First off ((((A+B)A'+C)+B') is not POS. Think of the name. A "product" of "sums". That means something of the form:


    Second, are you sure that ((((A+B)A'+C)+B') even describes your circuit? This says that if B is LO that the output is HI. Is that true?

    Next consider what happens if you apply DeMorgans to the SOP form.
    Last edited: Apr 17, 2013