boolean algebra help

Discussion in 'Homework Help' started by llkkjj, May 16, 2010.

  1. llkkjj

    Thread Starter New Member

    May 16, 2010
    1
    0
    hi, im stuck with this boolean algebra.

    F = (X + Y + X . Z) . (Y +X')

    btw: the law A + AB = A
    so does A + AB' = A?

    thanks in advance
     
  2. mel8030

    New Member

    Dec 24, 2009
    2
    0
    yes, A+AB'=A----> its telling you it does not matter what b' is

    change order so you can see the form A+AB

    F=(X+XZ+Y) (Y+X')
    =[(X+XZ)+Y] (Y=X')

    X+XZ =======> A+AB

    =(X+Y)(Y+X')

    Then could multiply out and use:
    XX'=0
    YY=Y
    and look for the form A+AB=A again
     
    Last edited: May 16, 2010
  3. Suket11

    New Member

    May 22, 2010
    3
    0
    A + AB = A.(1+B) = A.1 = A

    A + AB' = A.(1+B') = A.1 = A

    Anything in OR operation with 1 results 1...

    Your Ques. Ans . = Y
     
Loading...