i did in the past boolean algebra but i forgot it, can any1 try to help me out on this?
problem 1:
F(wxyz)= wx+xyz+x'yz+x'yz'+[wx+w' (x+z)]
i did this but i got stacked.
F(wxyz)= wx+xyz+x'yz+x'yz'+[wx+w' (x+z)]
= wx+xyz+x'y(z+z')+[wx+w' (x+z)]
=wx+xyz+x'y+(w'+x')wx.wz
=wx+xyz+x'y
can any1 tell me if i made a mistake? if its going to simplify more?
also i got this one:
problem 2: f(a,b,c)= a'b'c+a'bc'+ab'c+abc'+abc i did this:
=a'b'c+a'bc'+ab'c+ab(c'+c)
=a'b'c+a'bc'+ab'c+ab
=a'b'c+a'bc'+ac+a
=a'b'c+a'bc'+a
can any1 tell me if i made a mistake? if its going to simplify more?
tnx a lot for reading!
problem 1:
F(wxyz)= wx+xyz+x'yz+x'yz'+[wx+w' (x+z)]
i did this but i got stacked.
F(wxyz)= wx+xyz+x'yz+x'yz'+[wx+w' (x+z)]
= wx+xyz+x'y(z+z')+[wx+w' (x+z)]
=wx+xyz+x'y+(w'+x')wx.wz
=wx+xyz+x'y
can any1 tell me if i made a mistake? if its going to simplify more?
also i got this one:
problem 2: f(a,b,c)= a'b'c+a'bc'+ab'c+abc'+abc i did this:
=a'b'c+a'bc'+ab'c+ab(c'+c)
=a'b'c+a'bc'+ab'c+ab
=a'b'c+a'bc'+ac+a
=a'b'c+a'bc'+a
can any1 tell me if i made a mistake? if its going to simplify more?
tnx a lot for reading!