# Boolean Algebra Help

Discussion in 'Math' started by juanc2719, Mar 20, 2008.

1. ### juanc2719 Thread Starter New Member

Mar 20, 2008
2
0
I have a project and i dont know how i do this, please if someone can solve only this one with all the steps. i have to simplify this using boolean algebra

A'B'D + A'BD' + BC'D' + BCD' + AB'C'D + B'CD

2. ### Dave Retired Moderator

Nov 17, 2003
6,960
143

Firstly, common factors. Secondly, look at using the core Boolean identities.

Have a go and post up you attempts. From there we can give you feedback and point you in the right direction if need be.

Dave

3. ### chesart1 Senior Member

Jan 23, 2006
269
1
You resolve the problem with the boolean laws.

If you look carefully at your problem, you will see two terms that can be simplified.
BC'D' + BCD'

You know that C + C' = 1

Therefore first you separate BD' like this...

BCD' + BC'D' = BD'(C + C')

And then you equate C+C' to 1

BD'(C + C') = BD'(1) = BD'

Use the Booleans laws to resolve the rest of the problem. It may seem difficult at first but as you practice, it will get easier.