If I have an expression A.B'.C.D + (A'+B+C+D') can I write use De Morgan's law on the 2nd part of it to become A.B'.C.D + (A.B'.C'.D)?
Is A'+B+C+D' = A.B'.C'.D??
Is A'+B+C+D' = A.B'.C'.D??
Thread starter | Similar threads | Forum | Replies | Date |
---|---|---|---|---|
which of the following boolean algebra expression is incorrect? | Homework Help | 3 | ||
Boolean Algebra question | FPGAs (Field Programmable Gate Array) | 14 | ||
Boolean Algebra | Off-Topic | 0 | ||
R | Boolean algebra simplification | Homework Help | 22 | |
V | Boolean algebra excercises | Homework Help | 2 |
by Duane Benson
by Don Wilcher
by Aaron Carman
by Jake Hertz