BJT's

Discussion in 'General Electronics Chat' started by elly0007, May 7, 2009.

  1. elly0007

    Thread Starter New Member

    May 7, 2009
    3
    0
    I have a problem , how to explain a certain graph....

    i have a circuit of an NPN CC BJT with PNP diode-active load ... and the graph came from o V- 0.7V not a straight line its curved like and exponential graph . then after this region both Vin and Vout are linear (ie straight line is obtained ) ... can someone please explain how this graph is obtained , and which part is the active region and cutoff region.???

    thanks
    elly
     
  2. Ron H

    AAC Fanatic!

    Apr 14, 2005
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    You need to post the schematic and the graph.
     
  3. elly0007

    Thread Starter New Member

    May 7, 2009
    3
    0
    i attached the graph and the schematic ..
    thanks
     
  4. Ron H

    AAC Fanatic!

    Apr 14, 2005
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    Is the horizontal axis a sweep of V1?
     
  5. elly0007

    Thread Starter New Member

    May 7, 2009
    3
    0
    it is Vin against Vout .. Vin = (Vdc = 1.85)
     
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