Hi
I am having trouble with the following question
View attachment question4_BJTdiffamp.pdf
i don't understand why the value of Ic is 0.1293mA whilst i get 0.17966mA.
This i how i done it:
-3+18Ic+0.7+11.5Ic-3=0
6=18Ic+11.5Ic+0.7
6-0.7=(18+11.5)Ic
29.5Ic=5.3
Ic=0.17966mA
P.S
I am having trouble with the following question
View attachment question4_BJTdiffamp.pdf
i don't understand why the value of Ic is 0.1293mA whilst i get 0.17966mA.
This i how i done it:
-3+18Ic+0.7+11.5Ic-3=0
6=18Ic+11.5Ic+0.7
6-0.7=(18+11.5)Ic
29.5Ic=5.3
Ic=0.17966mA
P.S