# BJT Differential Amplifier DC Analysis

Discussion in 'Homework Help' started by TheRedDevil18, Feb 27, 2016.

1. ### TheRedDevil18 Thread Starter New Member

May 23, 2015
14
0

Vi1 = Vi2 = 3V dc
It = 2mA

For the diff amp above I have to perform a DC analysis and check if Q3 and Q4 are in active mode, so I have two equations

KVL at input
3 = Ib*R3 + Vbe + Ve
Ve = 3 - Ib*R3 - Vbe

KVL at supply
12 = Ic*R1 + Vce + Ve

Ie = It/2 = 2/2 = 1mA

If Ic approx = Ie then Ic = 1mA

The Beta value wasn't given so how do I find Ib ?

2. ### dannyf Well-Known Member

Sep 13, 2015
1,782
360
The tail is a 2ma ccs. So each leg gets 1ma. Base is at 3v, emitters at 3 minus 0.7v, and collector at 12v minus 4.7k x 1ma.

Pretty clear and shut.

As to beta, you typically assume that it is sufficiently large here.

3. ### TheRedDevil18 Thread Starter New Member

May 23, 2015
14
0
Yes thanks, that's what I thought initially. The resistance R6 (200 ohm), is that the emitter resistor for both the transistors ?

4. ### MrAl Well-Known Member

Jun 17, 2014
2,425
490
Hi,

Just a quick note...

R6 is a pot and with a completely symmetrical circuit that would be adjusted exactly half way, which puts 100 ohms in series with each emitter, but they would be considered separate resistors too.

Find the Beta from the data sheet for whatever transistors you are using.

Watch out that the collector voltage calculation is reasonable.

Last edited: Feb 27, 2016
5. ### dannyf Well-Known Member

Sep 13, 2015
1,782
360
R6 allows you to counter the imbalance between the two legs, and also to. Provide some degenerative power (DC feedback).

6. ### crutschow Expert

Mar 14, 2008
13,000
3,229
R6 also provides AC negative feedback.

7. ### TheRedDevil18 Thread Starter New Member

May 23, 2015
14
0
Ok, for the second part I have to determine the differential and common mode voltage gains. So is that R6 resistor just a separate 100 ohm resistor for each emitter of the bjt's ?

8. ### crutschow Expert

Mar 14, 2008
13,000
3,229
That's the equivalent circuit, yes.

9. ### TheRedDevil18 Thread Starter New Member

May 23, 2015
14
0
Will Rid (input differential resistance) be

Rid = Rib(input resistance from base) + R3 ?

Where Rib = ie(re + R6/2)/ib