BJT DC Biasing Question

Discussion in 'Homework Help' started by frozone45, Apr 16, 2016.

1. frozone45 Thread Starter New Member

Apr 16, 2016
2
0
For part b of the problem in the attached picture, I have determined that the upper limit for the value of VBB, for the transistor to remain active, is 15 [V]. I can not seem to find the lower limit for the value of VBB, for the transistor to remain active. Does anyone know what I am missing in my understanding of part b of the problem in the attached picture?

My attempt at answering the question is shown in the attached picture.

File size:
350.9 KB
Views:
21
2. Jony130 AAC Fanatic!

Feb 17, 2009
3,990
1,115
What is the base current if Vbb < 0.7V ?
Also Ie = Ib + Ic = Ib + β*Ic = (β + 1)*Ib

3. atferrari AAC Fanatic!

Jan 6, 2004
2,663
783
Ib + Ic = Ib + β*Ib

Jony130 likes this.
4. frozone45 Thread Starter New Member

Apr 16, 2016
2
0
(Negative value [V])/RB

5. MrAl Distinguished Member

Jun 17, 2014
2,542
512
Hello there,

Are you allowed to use the 0.7v constant base emitter voltage rule or not?
Also, do you have to consider collector to base leakage current?
Transistor and diode circuits are a little different than other circuits because the allowed assumptions have to be known beforehand and can vary widely from course to course.

In any case, the point where the transistor becomes inactive is when the base current times the Beta results in an output voltage Vc that is equal to the supply voltage Vcc. When that happens the output can no longer rise.

So you have to come up with an equation that relates Vbb to Vc and see what you can figure out.

Part of this depends on the above allowed assumptions however. For example, if you must consider leakage current then the max output Vc will be LESS than Vcc because there will be an ever present voltage drop in Rc.