I was watching this video on Troubleshooting Transistor Circuits which goes through circuit analysis on a common-emitter amplifier circuit. I have a few questions that didnt get answered in the video:
1) Why is it that an AC signal will see a power supply as a ground? I'll assume this doesn't apply to DC?
2) This is a multi-part question. When he calculated the AC collector current, he had to first calculate the *parallel* resistance of R4||R6 which are the "pull-up" resistor from collector to power supply and the load resistance respectively. The reason for it being a parallel calculation is the heart of Question #1 above.
Thank you for your help.
1) Why is it that an AC signal will see a power supply as a ground? I'll assume this doesn't apply to DC?
2) This is a multi-part question. When he calculated the AC collector current, he had to first calculate the *parallel* resistance of R4||R6 which are the "pull-up" resistor from collector to power supply and the load resistance respectively. The reason for it being a parallel calculation is the heart of Question #1 above.
- Did he ignore the series capacitance C3 (10uF) as a 1Khz AC signal will only see an additional reactance of only 16.91Ohm, basically a short?
- Did he neglect C2 for the same reason when calculating the emitter current?
Thank you for your help.