# BIASING

Discussion in 'General Electronics Chat' started by koley, Mar 3, 2006.

1. ### koley Thread Starter New Member

Mar 3, 2006
1
0
Could someone kindly help me with this assignment.

The diode current, i terms of voltaveV, is approximately given by
I=I.{exp(eV/kT)-1} where e=1.6^-19 coulomb is the electronic charge, k=1.38^-23joule k=boltzmann constant and T-temp. in K
if the saturation current I. is 1ηA, cal the forward and reverse resistances at V=0.2 and T=300K[/FONT]

Thanks a lot.

2. ### Papabravo Expert

Feb 24, 2006
10,338
1,850
I'm going to assume that V(reverse) = -V(forward) = -0.2 Volts

So
R(forward) = V(forward)/I(forward) = +0.2/I(forward)
R(reverse) = V(reverse)/I(reverse) = -0.2/I(reverse)

does that help?

By the way is this a germanium diode?

3. ### windoze killa AAC Fanatic!

Feb 23, 2006
605
24
Aren't germanium diodes dead and buried and pushing up daisies?????

Or should that be pushing up geraniums?????

Just some sick humour. Please forgive me and even ignore me.

Sorry. Couldn't resist.

4. ### Papabravo Expert

Feb 24, 2006
10,338
1,850
Apparently not
Germanium Diodes

5. ### beenthere Retired Moderator

Apr 20, 2004
15,815
283
Hi,

Just bought some 1N34's - you just never know when they'll come in handy. Might even save an oatmeal box and wind a coil some day.

6. ### aac Active Member

Jun 13, 2005
35
0
The small signal equivalent conductance can be found by taking the derivative of the current equation with respect to V.

dI.{exp(eV/kT)-1}/dV = I.{exp(eV/kT)}*(e/kT)

Just put .2 and -.2 in calculate the conductance and divide into 1 to get resistance.