Hello, I have a project presentation Friday. Unfortunately my current draw calculation was WAY off and I've just now realized this thing guzzles down 9v batteries very fast! I'm looking for a quick fix to get me through Friday and it seems switching from a alkaline to Lithium 9v battery will do the trick. My device draws about 60mA in its idle state and a little over half and amp in its active state.
The good news is it doesn't have to last very long, 30 minutes tops, the bad news is I'm having some trouble understanding the Capacity Characterization chart on the following datasheet
https://cellpacksolutions.co.uk/wp-...06/ultralife-u9vl-jp-technical-data-sheet.pdf
My device has two regulators, a 7805C and a MCP1827S-3302E/AB so I NEED the 9v battery to maintain at least 7.5 volts for about 30 minutes. This thing will only be in its active state one time during presentation so I won't have to worry about a large current draw.
So just to sum it all up, can I draw about 60mA for 25 minutes and still have enough juice to enter my active state? Could someone clarify for me? Thanks!
The good news is it doesn't have to last very long, 30 minutes tops, the bad news is I'm having some trouble understanding the Capacity Characterization chart on the following datasheet
https://cellpacksolutions.co.uk/wp-...06/ultralife-u9vl-jp-technical-data-sheet.pdf
My device has two regulators, a 7805C and a MCP1827S-3302E/AB so I NEED the 9v battery to maintain at least 7.5 volts for about 30 minutes. This thing will only be in its active state one time during presentation so I won't have to worry about a large current draw.
So just to sum it all up, can I draw about 60mA for 25 minutes and still have enough juice to enter my active state? Could someone clarify for me? Thanks!