# Basic Power source analysis

Discussion in 'Homework Help' started by choboko, Jun 29, 2010.

1. ### choboko Thread Starter New Member

Jun 2, 2009
5
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So maybe I'm overthinking or something but here's the question:

Power outlet open-circuit voltage is measured at exactly 240V. The fan heater(rated at 240V and 2kW) is connected to outlet and voltage V drops to 236.4V. Find the Series resistance (Rs).

From the previous question I calculated the load resistance (Rl) to be 28.8ohms (V^2/P) - to which i checked the answers and is correct. However for Rs it's 04386 ohms and I have no idea how they got that.

Any help would be great.

2. ### tskaggs New Member

Jun 17, 2010
26
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Have you tried figuring out the load current and working backwards?

3. ### choboko Thread Starter New Member

Jun 2, 2009
5
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Not quite sure what to do after that

4. ### choboko Thread Starter New Member

Jun 2, 2009
5
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i get a current value of (236.4/0.4386) = 538.99A...then where to go from there?

Mar 6, 2009
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