bandwidth required for the transmission line of aPCM

Discussion in 'General Electronics Chat' started by muni, Aug 23, 2008.

  1. muni

    Thread Starter Active Member

    Jul 29, 2008
    45
    0
    bandwidth required for the transmission line of a PCM signal increases by afactor of------------------------------- when the number of quantisation levels are increased from 4 to 64.


    sir request answer with little explanation.


    in the book it is given some thing like this way

    V1 = log (base 2) 4 =2
    C= 2b LOG (BASE 2) N; B=C/4

    V2 = log (base 2) 64 =6; B= C/12

    therefore BW = (C/12) / (C/3) =1/4

    request little more clear explanation on this
     
  2. studiot

    AAC Fanatic!

    Nov 9, 2007
    5,005
    513
    _{}Not sure where your difficulty lies.

    The quantized signal is mapped to a binary word
    Obviously the greater the number of quantizing levels the longer the binary word.

    Each of the M levels is mapped to one of N bits in the binary word

    N = log_{2}(M) or M = 2^{N}

    The rest is simply calculating this for M= 4 and M =64 and taking the ratio to obtain the fraction required.
     
  3. muni

    Thread Starter Active Member

    Jul 29, 2008
    45
    0
    sir, thankyou for giving me explanation and the formulae. though i was knowing this formulae, i wasn't clear how to use over this problem.

    once again thank you sir
     
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