Average power in a RLC circuit

Discussion in 'Homework Help' started by notoriusjt2, Sep 18, 2010.

  1. notoriusjt2

    Thread Starter Member

    Feb 4, 2010
    209
    0
    A voltage source of v(t) = 10 sin(1000t) V is connected to a load that is a parallel combination of a resistor, an inductor, and a capacitor. If R = 5 ohms , L = 5 mH , and C = 200 uF , determine the average power absorbed by the load.

    so in my professor's online notes it states this
    AVERAGE POWER ABSORBED BY A CAPACITOR IS ZERO FOR STEADY STATE PERIODIC OPERATION
    and
    AVERAGE POWER ABSORBED BY AN INDUCTOR IS ZERO FOR STEADY STATE PERIODIC OPERATION

    if these statements are true then do I just disregard the L and C in the circuit? v(t) = 10sin(1000t)v and R = 5ohms

    using ohms law calculate P=V^2/R = 20a. i already know this answer is wrong.

    what am I leaving out?


     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    The power will be Vrms^2/R.

    Vrms=10/√2
     
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