Is it that simple?Since P = V^2/R,
Make V^2 = 10 arbitrarily and use 10/20.8 and 10/18.7, the difference in power will be a lot less. e.g. 5% or so. Add the inaccuracies of your measurement and I think it comes out in the wash.
Everyone agrees with Keepitsim...?
I mean, I know a difference between left headphone 18.6 ohm and right headphone 18.1 ohm wouldn't make a difference, but in my case it's 19 ohm vs 21 ohm, they're not that close.