asynchornous counter

Thread Starter

5465da

Joined Dec 28, 2012
2
Question

1)In an asynchronous counter what is the frequency of the fifth flip flop when the clock input is 128khz?

Is it 4KHz?
since there is five flip flop divide by 2, five time?


2)A 3 bit johnson counter output is 800kHz, what is the input of it?
Is it 1.6MHz?
800kHz x 2 =1.6MHz ??????

I just wan to confirm with the answer
 
Last edited:

WBahn

Joined Mar 31, 2012
29,978
You answer to the first one is sound and so is your reasoning.

For the second one, describe the behavior of an n-bit Johnson counter. Is that consistent with your reasoning and answer?
 

Thread Starter

5465da

Joined Dec 28, 2012
2
You answer to the first one is sound and so is your reasoning.

For the second one, describe the behavior of an n-bit Johnson counter. Is that consistent with your reasoning and answer?
second wan
2x3=6 since it is a johnson counter
Mod 6
Formula
Input= Mod x output
so 6 x 800khz = 4.8MHz Right????
 

WBahn

Joined Mar 31, 2012
29,978
Correct (assuming that by "output frequency" they mean that the counter returns to the same state 800k times per second).
 
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