area and average of periodic signals

Discussion in 'Homework Help' started by bhuvanesh, Mar 4, 2015.

  1. bhuvanesh

    Thread Starter Member

    Aug 10, 2013
    268
    2
    area of periodic signal

    <br />
X_{avg} \; = \; \int_{-\infty}^{+\infty} x(t) dt<br />

    average of periodic signal

    <br />
X_{avg} \; = (1/T)\; \int_{-\infty}^{+\infty} x(t) dt<br />

    am i right?
     
  2. WBahn

    Moderator

    Mar 31, 2012
    17,736
    4,789
    Are you looking for total area or net area?

    If your integration limits are from -∞ to +∞, what is your period T.

    Why are you using the same parameter, Xavg, for both. This implies that they are equal.
     
  3. bhuvanesh

    Thread Starter Member

    Aug 10, 2013
    268
    2
    sorry i dont aware of coding that much its just copy of your last post to me on even and odd title question

    net area is something integrated over some period and total area is area over full interval

    example y=x limt -2 to 2
    area under 0 to 2 give net area(excluding negative axis curve) and are under -2 to 2 give total area isnt it?

    Then sure my limit is infinity

    <br />
X_{area} \; = \; \int_{-\infty}^{+\infty} x(t) dt<br />



    <br />
X_{avg} \; = (1/T)\; \int_{-\infty}^{+\infty} x(t) dt<br />
     
Loading...