could some one please give me a helping hand with this . a circuit consists of a 300 Ω resistor in series with a 3H coil and a 5μF capacitor. Determine the tangent of the angle of phase difference between the current and the applied emf when the frequency is A) 50Hz B) 25Hz for the 50Hz circuit i have worked out the impedance as 319 ohms. But not sure if i need this?
For 50Hz: impedance of L= j942.48 ohm impedance of C= -j636.62 ohm impedance of R= 300 ohm Total impedance =300 + j942.48 - j636.62 =300 + j305.86 Convert in polar form : 428.43 |__45.55 degrees if you assume the voltage to have an angle of 0 degrees then the current will lack the voltage by 45.55 degrees. You say to find this 'the tangent of the angle of phase difference' : i guess is the tanget of 45.55 degrees which equals 1.019 Go on for the 25Hz