Amplifier Circuits

Discussion in 'The Projects Forum' started by milanbarosh, Jan 28, 2009.

  1. milanbarosh

    Thread Starter New Member

    Jan 28, 2009
    4
    0
    Hello Folks

    Needing some help with the project I am doing. Just now I have a circuit that is driven by a 50Hz CW signal that is fed into a high power amplifier and is used to drive a load. The output from the amplifier has to be about 100-200V. Now, I need to replace the amplifier with some electronics circuitary but I do not know where I can find info or even where to start. If anyone can help it will be much appreciated or if there any other details you need ask away.

    Cheers

    Milan
     
  2. beenthere

    Retired Moderator

    Apr 20, 2004
    15,815
    282
    Some description of
    would be helpful. What is this circuitry supposed to do?
     
  3. milanbarosh

    Thread Starter New Member

    Jan 28, 2009
    4
    0
    Basically I want to replace the amplifier with a circuit that can amplify a 10mVp-p 50HZ signal to about 100-200V
     
  4. kahafeez

    Active Member

    Dec 2, 2008
    150
    0
    @ Milan..... keep this in mind that the amplifiers them self donot create any voltage.... they take it from the supply voltage given to them.....u'll have to give the amplifier this level thats 100-200V.....
     
  5. beenthere

    Retired Moderator

    Apr 20, 2004
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    In essence, you wish to replace the amplifier you have now with an equivalent one?
     
  6. milanbarosh

    Thread Starter New Member

    Jan 28, 2009
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    yes! Amplifier im using just now is too expensive and so im looking to replace it with an amplifier circuit
     
  7. milanbarosh

    Thread Starter New Member

    Jan 28, 2009
    4
    0
    I dont really understand what you mean here. Could you maybe explain a little?
     
  8. beenthere

    Retired Moderator

    Apr 20, 2004
    15,815
    282
    That means that the amplifier has to have within it the source for the output voltage and current to drive the load.

    You say -
    - but this is hard to understand. How can replacing one device with another that functions in the same way be less expensive?
     
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