# amplifier circuit

Discussion in 'Homework Help' started by labhelp, Feb 4, 2010.

1. ### labhelp Thread Starter New Member

Jan 28, 2010
28
0
Problem 2 Assume an A amplifier has an input impedance of 100K, an output impedance of 40Ω, and a nominal dc gain of 150. If the circuit is driving a 100Ω load with a signal generator that has an output impedance of 50Ω and an open-circuit output voltage of 0.5sin(500t+30o), determine the steady state output voltage.

I'm having trouble visualizing this circuit could someone help me out?

2. ### GirishC Active Member

Jan 23, 2009
58
0
The attachment will give you overall circuit block dia.

All now you need to use simple voltage divider formula and find out the output voltage across the load

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3. ### jstrike21 Member

Sep 24, 2009
104
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Thats what i was thinking it was

4. ### labhelp Thread Starter New Member

Jan 28, 2010
28
0
Vx=100k/(100k+50)*(.5)=.49975
150(.49975)=74.9625
Vout=(100/(100+40))*(74.9625)
=53.54V

right?

5. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
782
The answer looks fine - the only issue may be how many significant figures should be used. You have used two which is sufficient to differentiate the case in which the 50 Ω source impedance is ignored.