amplifier circuit

Discussion in 'Homework Help' started by labhelp, Feb 4, 2010.

  1. labhelp

    Thread Starter New Member

    Jan 28, 2010
    28
    0
    Problem 2 Assume an A amplifier has an input impedance of 100K, an output impedance of 40Ω, and a nominal dc gain of 150. If the circuit is driving a 100Ω load with a signal generator that has an output impedance of 50Ω and an open-circuit output voltage of 0.5sin(500t+30o), determine the steady state output voltage.

    I'm having trouble visualizing this circuit could someone help me out?
     
  2. GirishC

    Active Member

    Jan 23, 2009
    58
    0
    The attachment will give you overall circuit block dia.

    All now you need to use simple voltage divider formula and find out the output voltage across the load
     
    • ckt.jpg
      ckt.jpg
      File size:
      15.2 KB
      Views:
      19
  3. jstrike21

    Member

    Sep 24, 2009
    104
    0
    Thats what i was thinking it was
     
  4. labhelp

    Thread Starter New Member

    Jan 28, 2010
    28
    0
    Vx=100k/(100k+50)*(.5)=.49975
    150(.49975)=74.9625
    Vout=(100/(100+40))*(74.9625)
    =53.54V

    right?
     
  5. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    The answer looks fine - the only issue may be how many significant figures should be used. You have used two which is sufficient to differentiate the case in which the 50 Ω source impedance is ignored.
     
Loading...