amplifier circuit

Thread Starter

labhelp

Joined Jan 28, 2010
28
Problem 2 Assume an A amplifier has an input impedance of 100K, an output impedance of 40Ω, and a nominal dc gain of 150. If the circuit is driving a 100Ω load with a signal generator that has an output impedance of 50Ω and an open-circuit output voltage of 0.5sin(500t+30o), determine the steady state output voltage.

I'm having trouble visualizing this circuit could someone help me out?
 

GirishC

Joined Jan 23, 2009
58
The attachment will give you overall circuit block dia.

All now you need to use simple voltage divider formula and find out the output voltage across the load
 

Attachments

t_n_k

Joined Mar 6, 2009
5,455
Vx=100k/(100k+50)*(.5)=.49975
150(.49975)=74.9625
Vout=(100/(100+40))*(74.9625)
=53.54V

right?
The answer looks fine - the only issue may be how many significant figures should be used. You have used two which is sufficient to differentiate the case in which the 50 Ω source impedance is ignored.
 
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