I want to find the transfer function of this circuit, and I start by finding the voltage at the positive input of op-amp 1. If my understanding is correct, voltage division gives
\(V_+ =\frac{V_i}{1 + jwC_1 R_1}\)
If the op-amp is assumed to be ideal, this will also be the voltage at the negative input, and since there is no voltage drop on the line between the negative input and the uotput, the output of this op-amp has no gain. Is this correct so far?